(27x^-1/2)+(12x^1/2)

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Solution for (27x^-1/2)+(12x^1/2) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(12*x^1)/2+(27*x^-1)/2 = 0

(12*x)/2+(27*x^-1)/2 = 0

6*x^1+27/2*x^-1 = 0

(6*x^2+27/2*x^0)/(x^1) = 0 // * x^2

x^1*(6*x^2+27/2*x^0) = 0

x^1

6*x^2+27/2 = 0

6*x^2+27/2 = 0

DELTA = 0^2-(4*6*(27/2))

DELTA = -324

DELTA < 0

x in { }

x belongs to the empty set

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